y^2+4.2y+4.41=0

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Solution for y^2+4.2y+4.41=0 equation: 



y^2+4.2y+4.41=0

a = 1; b = 4.2; c = +4.41;
Δ = b2-4ac
Δ = 4.22-4·1·4.41
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-4.2}{2}=-2+0.2/2$

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